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Postby rachelle1K » Mon Dec 02, 2019 11:52 pm

How can one determine the number of sites to which a ligand can combine to create a polydentate?

Kelvin Chung 1C
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Re: Polydentate

Postby Kelvin Chung 1C » Tue Dec 03, 2019 12:51 am

When the ligand binds to a central metal atom at two or more of its sites, it is considered a polydentate. You can tell where these sites are by looking for lone pairs. Usually I look for oxygens and nitrogens in the ligand to see if they have any lone pairs they can donate.
The shape of the ligand can also affect the number of sites it has to bind to a central metal atom.

For example, oxalate has four oxygens that each have available lone pairs. However, oxalate is a bidentate. Once bound to a central metal atom at two adjacent oxygens, the other two oxygens are on opposite sides in oxalate's planar shape to bind to the same metal atom.

Elizabeth Harty 1A
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Joined: Sat Jul 20, 2019 12:16 am

Re: Polydentate

Postby Elizabeth Harty 1A » Tue Dec 03, 2019 8:23 am

You can look at lone pairs.

Maya Beal Dis 1D
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Re: Polydentate

Postby Maya Beal Dis 1D » Tue Dec 03, 2019 12:36 pm

Does a double bond mean that the atom double bonded in a ligand cannot be the atom bonded to the central atom in a coordination complex because it can't rotate?

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