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Do transition metals follow the Octet Rule? I know that they would use their d orbital which is 10 valence electrons rather than the p-orbital's six. Would this mean that they become stable with 12 valence electrons when accounting the s-block too?
Transition metals often don't follow the octet rule since the octet rule only considers the s and p orbitals. Transition metals are located in the d block so they often use their d-orbitals when bonding.
As others have said, because transition metals have d-orbitals, they're definitely capable of producing expanded octets and breaking the octet rule, but also keep in mind that just because they're capable of producing an expanded octet, that doesn't mean they'll always form one. So there definitely may be instances where they will only hold 8 electrons despite being capable of holding more.
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