5 posts • Page 1 of 1
en is shorthand for the ethylenediamine ligand, which is bidentate. Since Br has one bonding site and there are two of them, plus the two bonding sites on the ethylenediamine ligand, there's a total of 4 bonding sites. Therefore the coordination number would be 4.
I got that one wrong too and Sapling popped up saying that en stands for "ethylenediamine" which is a bidentate molecule. Each molecule can bind to the TM twice, so (en)2 will occupy 4 bonding regions! This will help find out the coordination number.
en stands for ethlyenediamine and it is a bidentate ligand, meaning it can donate two electron pairs to the central transition metal cation. In other words, it can form two bonds with the metal. Knowing this, and knowing the compound formula is [Cd(en)Br2], we know that the coordination number will be 4, since en forms 2 bonds and each Br forms 1 bond, giving a total of 4 bonds.
Who is online
Users browsing this forum: No registered users and 1 guest