I'm having trouble figuring out this problem, could someone please explain I would complete it?
9C.7 Which of the following isomers of diaminobenzene can form chelating complexes? Explain your reasoning.
Homework Problem 9C.7
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Re: Homework Problem 9C.7
In order to form chelating complexes, you need bonds that can rotate (single bonds) and the the ideal geometry, which is (atom w/ lone pair) + (spacer) + (spacer) + (atom w/ lone pair)
In this case, the answer would be b) because a) and c) have too many spacers between atoms w/ lone pairs.
In this case, the answer would be b) because a) and c) have too many spacers between atoms w/ lone pairs.
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Re: Homework Problem 9C.7
Hi! The two amine groups in a and c are arranged so that they are not able to coordinate simultaneously to the same metal center. It is possible for them to form a bridging ligand, but that is not classified as chelating. Therefore, the only molecule that can function as a chelating ligand is b. I hope this helps!
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Re: Homework Problem 9C.7
Xinyu Li 2I wrote:In order to form chelating complexes, you need bonds that can rotate (single bonds) and the the ideal geometry, which is (atom w/ lone pair) + (spacer) + (spacer) + (atom w/ lone pair)
In this case, the answer would be b) because a) and c) have too many spacers between atoms w/ lone pairs.
Hi Xinyu, I had a quick question: in the molecule in part b of this problem, what are the spacer atoms? Is it the hydrogen atoms?
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Re: Homework Problem 9C.7
Cassidy Cheng 1J wrote:Xinyu Li 2I wrote:In order to form chelating complexes, you need bonds that can rotate (single bonds) and the the ideal geometry, which is (atom w/ lone pair) + (spacer) + (spacer) + (atom w/ lone pair)
In this case, the answer would be b) because a) and c) have too many spacers between atoms w/ lone pairs.
Hi Xinyu, I had a quick question: in the molecule in part b of this problem, what are the spacer atoms? Is it the hydrogen atoms?
Hey Cassidy, I believe the spacer atoms would be the atoms between the NH2. In (a) there are 4, in (b) there are 2, and in (c) there are 3.
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- Posts: 111
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Re: Homework Problem 9C.7
Ven Chavez 2K wrote:Cassidy Cheng 1J wrote:Xinyu Li 2I wrote:In order to form chelating complexes, you need bonds that can rotate (single bonds) and the the ideal geometry, which is (atom w/ lone pair) + (spacer) + (spacer) + (atom w/ lone pair)
In this case, the answer would be b) because a) and c) have too many spacers between atoms w/ lone pairs.
Hi Xinyu, I had a quick question: in the molecule in part b of this problem, what are the spacer atoms? Is it the hydrogen atoms?
Hey Cassidy, I believe the spacer atoms would be the atoms between the NH2. In (a) there are 4, in (b) there are 2, and in (c) there are 3.
Ohh, so would they be the carbon atoms then? Thanks so much!
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