Textbook Problem 9C.5

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vuongnaomi1L
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Joined: Wed Sep 30, 2020 9:56 pm

Textbook Problem 9C.5

Postby vuongnaomi1L » Sat Dec 12, 2020 7:10 am

In part d, the question asks the ligand can be polydentate, and give the maximum number of places on the ligand that can bind simultaneously to a single metal center. For oxalate ion, the formula is C2O4 2-. I attached a picture.

Since there are lone pairs on 4 of the atoms, what makes it bidentate and donating 2 electron pairs instead of donating 4 electron pairs (because there are lone pairs on 4 of the atoms).

vuongnaomi1L
Posts: 111
Joined: Wed Sep 30, 2020 9:56 pm

Re: Textbook Problem 9C.5

Postby vuongnaomi1L » Sat Dec 12, 2020 7:11 am

This is the pic, forgot to insert.
Attachments
Screen Shot 2020-12-12 at 7.06.27 AM.png
Screen Shot 2020-12-12 at 7.06.27 AM.png (16.64 KiB) Viewed 484 times

Arya Adibi 1K
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Re: Textbook Problem 9C.5

Postby Arya Adibi 1K » Sat Dec 12, 2020 9:18 am

Only two of the oxygen atoms can bind to metallic central atom, which makes it bidentate

claire ikemiya_2I
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Re: Textbook Problem 9C.5

Postby claire ikemiya_2I » Sat Dec 12, 2020 9:40 am

Which two oxygen atoms? Is it the ones with the single bonds?

Charlie Russell 2L
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Re: Textbook Problem 9C.5

Postby Charlie Russell 2L » Sun Dec 13, 2020 2:43 am

The single bonded oxygen atoms can make a coordinate covalent bond to another transition metal. It would make their formal charge zero if they did, as well, thus making this bidentate because of those two single bond atoms.

Simran Bains 2C
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Re: Textbook Problem 9C.5

Postby Simran Bains 2C » Sun Dec 13, 2020 2:46 am

The two single bonded Oxygen.


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