Achieve Homework #5, Question #2  [ENDORSED]

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trishaferrer
Posts: 92
Joined: Fri Sep 24, 2021 5:26 am

Achieve Homework #5, Question #2

Postby trishaferrer » Fri Nov 26, 2021 8:59 am

Hi! Is it okay if I could get help with this? Thanks!
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Meghan Spoeri 2D
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Re: Achieve Homework #5, Question #2  [ENDORSED]

Postby Meghan Spoeri 2D » Fri Nov 26, 2021 9:41 am

hi! The coordination number of a metal is equal to the total number of donor atoms from the ligands. In other words, the coordination number = number of bonds between the metal and ligands. Looking at the first compound, [Ni(CN)5]-3, the metal is Ni and it is bound to 5 CNs. Therefore, the coordination number is 5. For the compound K3[CoF6], you only focus on what is inside the brackets so Co is bound to 6 Fs. Therefore, the coordination number is 6. You basically use this logic for the rest of the compounds and sort them based on that. hope this helps!

Crystal Ma 2J
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Joined: Fri Sep 24, 2021 7:04 am

Re: Achieve Homework #5, Question #2

Postby Crystal Ma 2J » Fri Nov 26, 2021 5:55 pm

Hi,

Coordination number= number of ligands attached to the central ion so just count those after identifying the TM in the brackets!

Windell Viste 1K
Posts: 103
Joined: Fri Sep 24, 2021 7:30 am

Re: Achieve Homework #5, Question #2

Postby Windell Viste 1K » Fri Nov 26, 2021 6:59 pm

Like the others have said, coordination number is equal to the number of ligands attached to the central atom/metal atom. It would be the number of atoms within the brackets attached to the TM for each.

Travis Wang 2G
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Joined: Fri Sep 24, 2021 5:11 am

Re: Achieve Homework #5, Question #2

Postby Travis Wang 2G » Fri Nov 26, 2021 10:54 pm

I would like to point out that Ba[FeBr4]2 might be either an edge case or some sort of typo but looking at what's inside the brackets is still the way to classify this molecule.

Michelle Li 2B
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Re: Achieve Homework #5, Question #2

Postby Michelle Li 2B » Sat Nov 27, 2021 12:30 am

The coordination number is equal to the number of bonds formed between the central metal atom and the ligands. Since the coordination compound is within the brackets, you would only focus on the metal atom inside the brackets and how many bonds it is forming with the ligand which is also inside the brackets.

QUEP 2F
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Joined: Fri Sep 24, 2021 7:11 am

Re: Achieve Homework #5, Question #2

Postby QUEP 2F » Sat Nov 27, 2021 2:43 am

Hi!

Coordination number is defined as the number of ligands attached to the central ion. The coordination compound is enclosed by brackets (we only focus on what’s inside these brackets), so you would look to the metal atom and count how many bonds it forms with ligands. In K3[CoF6], Co is bound to 6 Fs, giving it a coordination number of 6.

205686400
Posts: 69
Joined: Fri Sep 24, 2021 5:44 am

Re: Achieve Homework #5, Question #2

Postby 205686400 » Sat Nov 27, 2021 3:17 am

Hi! To basically sum up what everyone is saying, you want to look at the number of bonds that the central atom makes, and by that I mean just count up the number of atoms inside the brackets (excluding the central atom) and that would be your coordination number. Be sure to remember that if there are -dentate molecules they can account for more than one bond. For example, a bidentate would count for two bonds rather than one.


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