Week 9 Achieve question 5

[Xinyue Zou 2K]

For [Pt(en)Cl2] how would you find the coordination number of Pt? I don't understand what (en) is supposed to represent and that's tripping me up.

[Crystal Ma 2J]

en represents Ethylenediamine or C₂H₄(NH₂)₂

[Ainsley McCabe 2D]

Are we supposed to know what en represents on the final or will we be given that formula?

[Janice Hu 2L]

(en) is the abbreviation for ethylenediamine when its a ligand. As for figuring out the coordination number, just remember that (en) is bidentate and Cl- is monodentate :)

[Jennifer Huynh 3I]

En is ethylenediamine, which is a bidentate that bonds to the metal at two positions. Two N atoms in en bind to the metal. Cl is a monodentate ligand that binds to the metal in one position.
coordination # = 2 + 2 = 4

[Janice Hu 2L]

Are we supposed to know what en represents on the final or will we be given that formula?

I think it would be safe to know it since Dr. Lavelle talked about it in one of his lectures.

[Heba Bounar 3K]

Hi! en is a bidentate ligand, meaning it binds to the transition metal at two locations. Cl is a monodentate ligand, meaning it binds to the transition metal in one location. Therefore, if you add up the total of binding locations, the coordination number of Pt is equal to 2 (from the en) + 2 (from the chlorines) = 4. Hope that helps!