Week 9 Achieve question 5
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Week 9 Achieve question 5
For [Pt(en)Cl2] how would you find the coordination number of Pt? I don't understand what (en) is supposed to represent and that's tripping me up.
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Re: Week 9 Achieve question 5
Are we supposed to know what en represents on the final or will we be given that formula?
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Re: Week 9 Achieve question 5
(en) is the abbreviation for ethylenediamine when its a ligand. As for figuring out the coordination number, just remember that (en) is bidentate and Cl- is monodentate :)
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Re: Week 9 Achieve question 5
En is ethylenediamine, which is a bidentate that bonds to the metal at two positions. Two N atoms in en bind to the metal. Cl is a monodentate ligand that binds to the metal in one position.
coordination # = 2 + 2 = 4
coordination # = 2 + 2 = 4
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Re: Week 9 Achieve question 5
Ainsley McCabe 2E wrote:Are we supposed to know what en represents on the final or will we be given that formula?
I think it would be safe to know it since Dr. Lavelle talked about it in one of his lectures.
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Re: Week 9 Achieve question 5
Hi! en is a bidentate ligand, meaning it binds to the transition metal at two locations. Cl is a monodentate ligand, meaning it binds to the transition metal in one location. Therefore, if you add up the total of binding locations, the coordination number of Pt is equal to 2 (from the en) + 2 (from the chlorines) = 4. Hope that helps!
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