Achieve #6

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905574994
Posts: 107
Joined: Fri Sep 24, 2021 7:26 am

Achieve #6

Postby 905574994 » Sat Nov 27, 2021 12:47 pm

Hi guys,

Could someone please walk me through how to find the oxidation number of this complex?

[Co(NH3)4Cl2]Cl

Thanks

Riya Sawhney 1C
Posts: 104
Joined: Fri Sep 24, 2021 5:07 am

Re: Achieve #6

Postby Riya Sawhney 1C » Sat Nov 27, 2021 12:54 pm

[Co(NH3)4Cl2]Cl

First, we know that ammonia, NH3, is net neutral, so the individual oxidation numbers in it must add up to zero. We don't need to know specifically what they are, just that ammonia is neural.

Next, we know that chlorine, both in the oxidation sphere and out of it have an oxidation number of -1, as chlorine gains an electron in a bond. So we have 3 -1 charges.

Finally, we know that the molecule as a whole is neutral. Therefore we know that colbalt has an oxidation state of +3, so it is named as colbalt (III).

Elsie_Lin_2K
Posts: 103
Joined: Fri Sep 24, 2021 5:08 am

Re: Achieve #6

Postby Elsie_Lin_2K » Sat Nov 27, 2021 1:11 pm

To add on, you could put the oxidation numbers as an equation it is easier to view what is positive and what is negative. In this case, you would write it as
x+ 4(0)+(-1)(2)-1=0; x=+3


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