17.35 Chelating Compounds

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Rachel Song 2A
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17.35 Chelating Compounds

Postby Rachel Song 2A » Sun Nov 29, 2015 9:45 pm

17.35 Which of the following isomers of diaminobenzene can form chelating complexes? Explain. (Pictures of the isomers not included)

What exactly are chelating complexes and how do we determine that an isomer can form a chelating complex?

Chem_Mod
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Re: 17.35 Chelating Compounds

Postby Chem_Mod » Mon Nov 30, 2015 8:38 am

A chelating complex is a complex between a metal atom and polydentate ligand (i.e. a ligand that can bind multiple times to one metal atom). In this case, there are two binding sites on each of these isomers (the nitrogens have lone pairs, allowing them to donate electrons). The only isomer in which the nitrogens are close enough together to complex to the same metal atom is (b).

Kyla Grunden 1L
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Re: 17.35 Chelating Compounds

Postby Kyla Grunden 1L » Sat Nov 30, 2019 2:39 pm

How do you determine at what point the nitrogens are too far away to bond to the same metal atom?

Ruth Glauber 1C
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Re: 17.35 Chelating Compounds

Postby Ruth Glauber 1C » Sat Dec 07, 2019 8:51 pm

I also had this question! ^^

Ashley Nguyen 2L
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Re: 17.35 Chelating Compounds

Postby Ashley Nguyen 2L » Sat Dec 07, 2019 9:08 pm

Kyla Grunden 1L wrote:How do you determine at what point the nitrogens are too far away to bond to the same metal atom?


I think it's more of a common sense thing. If the nitrogens are on complete opposite sides of the benzene ring, it would be impossible for them to bond to the same metal atom. The ideal distance is nitrogen - spacer atom - spacer atom - nitrogen, where the spacer atoms are the carbons in the example.

Connor Ho 1B
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Re: 17.35 Chelating Compounds

Postby Connor Ho 1B » Sat Dec 07, 2019 9:11 pm

Kyla Grunden 1L wrote:How do you determine at what point the nitrogens are too far away to bond to the same metal atom?


I believe Lavelle responded to a question about coordination compounds, and in his answer he says that there can be two spacer compounds in between a bonding area.


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