Hey!
How do you determine the denticity of a ligand?
Thanks!
denticity
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 101
- Joined: Fri Sep 24, 2021 6:02 am
Re: denticity
I think the best way is to look at the structure and determine how many bonds it can form.
-
- Posts: 104
- Joined: Fri Sep 24, 2021 5:07 am
Re: denticity
Denticity refers to the number of bonds a single ligand can form with a central atom.For example, EDTA, shown below, is hexadentate, meaning it can form 6 bonds. Sigma bonds can rotate, and so parts of the molecule can rotate into the correct position.
-
- Posts: 110
- Joined: Fri Sep 24, 2021 6:41 am
- Been upvoted: 1 time
Re: denticity
To add on to the previous answer, for a ligand to be bidentate, it needs to include an "atom with a lone pair - spacer atom - spacer atom - atom with a lone pair" structure. For example, ethylene diamine (NH2 - CH2 - CH2 - NH2) is bidentate because each of its nitrogen atoms have a lone pair and are separated by two carbon atoms that are "spacers". Combining multiple of these "atom - spacer - spacer - atom" structures can result in molecules that have a higher denticity (such as EDTA).
Hopefully this helps and please correct me if there are any mistakes.
Hopefully this helps and please correct me if there are any mistakes.
Return to “Shape, Structure, Coordination Number, Ligands”
Who is online
Users browsing this forum: No registered users and 16 guests