Oxidation Number

[Alexis DeHorta 2A]

Hello! I was wondering when I have a compound with a charge on the outside, do we include this in our calculations when we are solving for the oxidation number?

Example:
X+6(0)+3 = 0
X + 0 +3 = 0
X + 3 = -3
Would this be the Oxidation number of the compound? Or would we not include the charge on the outside of the brackets?

[Lily Dabrowski 2G]

The charge on the outside of the brackets would be used. NH3 is neutral so we can ignore it for the charge. So now we need to determine was the charge of Co needs to be to get the whole compound's state to equal the charge on the outside, 3+. Co would then need to have an oxidation number of 3+.

[Cory Poon 3G]

X+6(0) = +3
X + 0 = +3
X = +3
Would be the correct math here! The +3 for the overall compound should be on the other side of the = sign!

[005683006]

THe oxidation number is the charge of the central metal ion

[Samidha Menon 1E]

The oxidation number would be 3+, the charge on the metal ions.

[Samidha Menon 1E]

The oxidation number would be 3+, the charge on the metal ions.

[Aparna Pillai 1E]

Hi! To answer your question, one of the rules for oxidation numbers is that the sum of all oxidation numbers in a polyatomic ion is equal to the charge on the ion (in this case, they would add up to 3+).

[Michelle Gong]

Yes, you would count the outside charge to find the oxidation numbers because the molecules still have to have a neutral charge overall, unless it is an ion.

[sophiavmr]

Yes, that would be the correct math in the second one