Homework Problem 11.41

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Cobie_Allen_1H
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Joined: Wed Sep 21, 2016 2:56 pm

Homework Problem 11.41

Postby Cobie_Allen_1H » Fri Nov 18, 2016 7:46 pm

Hey guys! I had a question on the homework. I just got a little confused.

11.41. A 25.0-g sample of ammonium carbamate, NH4(NH2CO2), was placed in an evacuated 0.250-L flask and kept at 25 degrees Celsius. At equilibrium, 17.4mg of CO2 was present. What is the value of Kc for the decomposition of ammonium carbamate into ammonia and carbon dioxide? The reaction is NH4(NH2CO2)(s) <---> 2NH3(g) + CO2(g).

Thanks for the help!

Hao 1I
Posts: 26
Joined: Wed Sep 21, 2016 3:00 pm
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Re: Homework Problem 11.41

Postby Hao 1I » Sun Nov 20, 2016 8:56 pm

Start with the ICE chart and and convert the grams of CO2 to moles. Then knowing that there are 2 moles of NH3 for every one mole of CO2, moles of CO2 will be doubled for NH3. Be aware that NH4(NH2CO2) is a solid!

Cobie_Allen_1H
Posts: 24
Joined: Wed Sep 21, 2016 2:56 pm

Re: Homework Problem 11.41

Postby Cobie_Allen_1H » Mon Nov 28, 2016 10:49 am

Thank you so much for the help! Really appreciate it!

Angela_Pu_3C
Posts: 22
Joined: Fri Jul 15, 2016 3:00 am

Re: Homework Problem 11.41

Postby Angela_Pu_3C » Mon Nov 28, 2016 1:21 pm

Why do we plug in 1.581x10-3? The x (or molar concentration of CO2) is 1.581M (resulting in Kc=1.58) so I'm not sure how/why we use 1.581x10-3 instead.


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