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Homework Problem 11.41

Posted: Fri Nov 18, 2016 7:46 pm
by Cobie_Allen_1H
Hey guys! I had a question on the homework. I just got a little confused.

11.41. A 25.0-g sample of ammonium carbamate, NH4(NH2CO2), was placed in an evacuated 0.250-L flask and kept at 25 degrees Celsius. At equilibrium, 17.4mg of CO2 was present. What is the value of Kc for the decomposition of ammonium carbamate into ammonia and carbon dioxide? The reaction is NH4(NH2CO2)(s) <---> 2NH3(g) + CO2(g).

Thanks for the help!

Re: Homework Problem 11.41

Posted: Sun Nov 20, 2016 8:56 pm
by Hao 1I
Start with the ICE chart and and convert the grams of CO2 to moles. Then knowing that there are 2 moles of NH3 for every one mole of CO2, moles of CO2 will be doubled for NH3. Be aware that NH4(NH2CO2) is a solid!

Re: Homework Problem 11.41

Posted: Mon Nov 28, 2016 10:49 am
by Cobie_Allen_1H
Thank you so much for the help! Really appreciate it!

Re: Homework Problem 11.41

Posted: Mon Nov 28, 2016 1:21 pm
by Angela_Pu_3C
Why do we plug in 1.581x10-3? The x (or molar concentration of CO2) is 1.581M (resulting in Kc=1.58) so I'm not sure how/why we use 1.581x10-3 instead.