Question 11.39

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Annah Khan 1B
Posts: 28
Joined: Fri Jul 22, 2016 3:00 am

Question 11.39

Postby Annah Khan 1B » Sun Jul 30, 2017 5:30 pm

"Use the information in Table 11.2 (pg. 428) to determine the value of K at 300 K for the reaction 2 BrCl (g) + H2 (g) <--> Br2 (g) + 2 HCl (g)."

I understand the concept of the question and what it is asking, but I am not sure how to solve it and why that would be the answer. If someone could please explain this to me, that would be great! Thank you in advance!

Odalis Section 1E
Posts: 20
Joined: Wed Nov 16, 2016 3:03 am

Re: Question 11.39

Postby Odalis Section 1E » Sun Jul 30, 2017 6:21 pm

Well you are given this equation at 300 K and as you can see the equation you're given is two equations on the chart 11.2 combined. You can say that they are multiplied into one equation so you would look at both these equations on the chart at 300 and multiply their Kc.

Sarina Morales 1D
Posts: 14
Joined: Tue Nov 08, 2016 3:00 am

Re: Question 11.39

Postby Sarina Morales 1D » Sun Jul 30, 2017 7:32 pm

wouldn't we add the Kc values? I'm also having trouble with this problem and I'm not quite sure which two base equations to look at, from the chart.

Laura Riccardelli
Posts: 49
Joined: Fri Sep 29, 2017 7:04 am

Re: Question 11.39

Postby Laura Riccardelli » Tue Nov 21, 2017 3:41 pm

Look at the base equations H2 + Cl2= 2HCl and 2BrCl=Br2 = Cl2 which have corresponding K values and multiply those K values together.


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