11.117 (b)

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Maria1E
Posts: 61
Joined: Sat Jul 22, 2017 3:01 am

11.117 (b)

Postby Maria1E » Tue Nov 21, 2017 10:51 am

SO3 (g) + NO (g) --> SO2 (g) + NO2 (g)

117 b) Given that at a certain temperature K = 6.0 x 10^3, calculate the amount (in moles) of NO that must be added to a 1.00 L vessel containing .245 mol SO3 (g) to form .240 mol SO2 (g) at equilibrium.

How do you go about solving this? Thank you!

mayasinha1B
Posts: 70
Joined: Fri Sep 29, 2017 7:04 am

Re: 11.117 (b)

Postby mayasinha1B » Tue Nov 21, 2017 12:03 pm

Because you are given both moles and volume of each of the products and reactants except for NO, you can calculate each of their concentrations. Plugging in to the equilibrium equation using concentrations, you can solve for concentration of NO. Given it is in a 1 L container, you can use the concentration to calculate moles of NO.


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