Ch 11 #47

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donnanguyen1d
Posts: 64
Joined: Fri Sep 29, 2017 7:04 am

Ch 11 #47

Postby donnanguyen1d » Fri Nov 24, 2017 11:29 pm

When finding the percentage of PCl5 that has decomposed at equilibrium why couldn't we divide .009 ([PCl5] at equilibrium)/.019? why did the solutions round .009 to .01? Not rounding would give 47% but rounding would give 53%? it's a pretty big difference, would it matter if we rounded or not?

Ashin_Jose_1H
Posts: 51
Joined: Fri Sep 29, 2017 7:04 am

Re: Ch 11 #47

Postby Ashin_Jose_1H » Sat Nov 25, 2017 8:13 pm

Since, x=.01 M, the final concentration at Equilibrium for PCl5 is .009 M. This means that .01M of PCl5 has decomposed.

Initial Concentration- Final Concentration= Concentration decomposed
(.019M) - (.009 M) = .010M

Therefore, it would be .01M divided by .019M (Concentration decomposed Divided by Initial Concentration) = 53%

Hope this helps.


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