11.45 part c

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Kyra LeRoy 1E
Posts: 52
Joined: Sat Jul 22, 2017 3:00 am

11.45 part c

Postby Kyra LeRoy 1E » Sun Nov 26, 2017 7:36 pm

For part C, it asks whether Cl2 or F2 is more thermodynamically stable relative to its atoms at 1000. K. How exactly do we figure out which is more stable?

I got that the concentration for each is:
Cl2 .001 mol/L
Cl 1.1x10^-5 mol/L
F2 8x10^-4 mol/L
F 3.2x10^-4 mol/L


Sean Monji 2B
Posts: 66
Joined: Fri Sep 29, 2017 7:06 am

Re: 11.45 part c

Postby Sean Monji 2B » Sun Nov 26, 2017 9:41 pm

Stability means that the molecule is less likely to dissociate, or less likely to become un-bonded. That means in the given reactions, (CL2 -> 2CL or F2 -> 2F) the more stable molecule will have more of the reactant (the bonded molecule), and therefore a lower Kc since Kc is product divided by reactant. This means that the molecule with the lowest Kc will be more stable since it is more likely to stay in its bonded state. Through your calculations, you can find that the that Kc of chlorine is smaller than fluorine in these reactions, so chlorine must be more stable. Hope that helps

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