11.41

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Magdalena Palavecino 1A
Posts: 54
Joined: Fri Sep 29, 2017 7:04 am

11.41

Postby Magdalena Palavecino 1A » Sun Nov 26, 2017 9:37 pm

Can someone please explain what method we are supposed to use to solve 41?

Naama 1A
Posts: 20
Joined: Fri Sep 29, 2017 7:04 am

Re: 11.41

Postby Naama 1A » Sun Nov 26, 2017 9:54 pm

You can figure out the equilibrium concentration of CO2 using the information given--convert 17.4mg CO2 to moles, then find the concentration by dividing by .250L. The ratio of CO2 to NH3 is 1:2, therefore the NH3 concentration is twice as much. Then use the Kc formula to get 1.58x10^-8 (remember the exponent on [NH3]!). You can also visualize this using the I.C.E. table. The NH4(NH2CO2) is not involved in these calculations because it is a solid.

Akash_Kapoor_1L
Posts: 52
Joined: Thu Jul 13, 2017 3:00 am
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Re: 11.41

Postby Akash_Kapoor_1L » Tue Nov 28, 2017 4:34 pm

I was confused about the same problem... Why do they give you the amount of ammonium carbamate and the temperature? Is there an alternate way of solving the problem that uses those two quantities??


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