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Natalie LeRaybaud 1G
Posts: 54
Joined: Thu Jul 13, 2017 3:00 am


Postby Natalie LeRaybaud 1G » Tue Nov 28, 2017 6:34 pm

Can someone please explain how to solve this question, using the quadratic formula?

A reaction mixture is prepared by mixing 0.100 mol SO2, 0.200 mol NO2, 0.100 mol NO, and 0.150 mol SO3 in
a 5.00-L reaction vessel. The reaction SO2(g) NO2(g) ∆ NO(g) SO3(g) is allowed to reach equilibrium at 460 C, when Kc 85.0. What is the equilibrium concentration of each substance?

Curtis Tam 1J
Posts: 105
Joined: Thu Jul 13, 2017 3:00 am

Re: 11.59

Postby Curtis Tam 1J » Tue Nov 28, 2017 7:26 pm

Calculate Q first to see which direction the reaction would go in. Then do an icebox calculation and set your equilibrium concentrations equal to k. Solve for x and plug those values back into the equilibrium concentrations.

chari_maya 3B
Posts: 108
Joined: Sat Sep 07, 2019 12:18 am

Re: 11.59

Postby chari_maya 3B » Sun Jan 19, 2020 3:54 pm

Calculate Q first, which should produce a value of Q = 0.75. Because Q < Kc, the reaction proceeds in the forward direction, so reactants will lose concentration while products will gain concentration. Then do the ICE table and use quadratic equation to find Kc.

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