Moderators: Chem_Mod, Chem_Admin

Natalie LeRaybaud 1G
Posts: 54
Joined: Thu Jul 13, 2017 3:00 am


Postby Natalie LeRaybaud 1G » Tue Nov 28, 2017 6:34 pm

Can someone please explain how to solve this question, using the quadratic formula?

A reaction mixture is prepared by mixing 0.100 mol SO2, 0.200 mol NO2, 0.100 mol NO, and 0.150 mol SO3 in
a 5.00-L reaction vessel. The reaction SO2(g) NO2(g) ∆ NO(g) SO3(g) is allowed to reach equilibrium at 460 C, when Kc 85.0. What is the equilibrium concentration of each substance?

Curtis Tam 1J
Posts: 105
Joined: Thu Jul 13, 2017 3:00 am

Re: 11.59

Postby Curtis Tam 1J » Tue Nov 28, 2017 7:26 pm

Calculate Q first to see which direction the reaction would go in. Then do an icebox calculation and set your equilibrium concentrations equal to k. Solve for x and plug those values back into the equilibrium concentrations.

chari_maya 3B
Posts: 108
Joined: Sat Sep 07, 2019 12:18 am

Re: 11.59

Postby chari_maya 3B » Sun Jan 19, 2020 3:54 pm

Calculate Q first, which should produce a value of Q = 0.75. Because Q < Kc, the reaction proceeds in the forward direction, so reactants will lose concentration while products will gain concentration. Then do the ICE table and use quadratic equation to find Kc.

Return to “Equilibrium Constants & Calculating Concentrations”

Who is online

Users browsing this forum: dana hu 1B and 1 guest