Chemical Equilibrium Part 2 Question #12

Moderators: Chem_Mod, Chem_Admin

Jessica Nunez 1I
Posts: 58
Joined: Thu Jul 13, 2017 3:00 am

Chemical Equilibrium Part 2 Question #12

Postby Jessica Nunez 1I » Wed Nov 29, 2017 8:20 pm

I'm a little confused on how to solve this problem that's in the Chemical Equilibrium Part 2 Module.

Consider the following reaction at 1200 K, for which you know Kc = 1.7 x 10-3.
Br2 (g) ⇌ 2 Br (g)
Your experimental setup is able to measure the equilibrium concentration of Br2 based on its color, but you are unable to measure the concentration of Br directly. If you measure at equilibrium [Br2] to be 1.02 x 10-4 M, calculate the equilibrium concentration of Br for this experiment.

A. [Br] = 8.7 x 10-8

B. [Br] = 1.7 x 10-7

C. [Br] = 4.2 x 10-4

D.None of the above

Naama 1A
Posts: 20
Joined: Fri Sep 29, 2017 7:04 am

Re: Chemical Equilibrium Part 2 Question #12

Postby Naama 1A » Wed Nov 29, 2017 8:48 pm

We use the equilibrium constant expression: Kc=[Br]^2/[Br2]. In this case, we know Kc and [Br2], so we simply solve for the unknown [Br], which ends up being C.


Return to “Equilibrium Constants & Calculating Concentrations”

Who is online

Users browsing this forum: No registered users and 2 guests