Table 11.2

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Hyein Cha 2I
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Table 11.2

Postby Hyein Cha 2I » Thu Nov 30, 2017 7:52 pm

Why are thevalues of K and Kc different for some of the reactions in table 11.2? Shouldnt they all be the same?

Minie 1G
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Re: Table 11.2

Postby Minie 1G » Thu Nov 30, 2017 10:43 pm

K is Kp, the equilibrium constant based on the partial pressures. The relationship between Kc and Kp is Kp = Kc(RT)^delta(n). This can be derived from the ideal gas equation (PV=nRT) by letting P = nRT/V (and n/V is the concentration, so this is P = [gas]RT) and plugging that in to the Kp equation (the products/reactants one) and simplifying.

Anyways, we see that since R and T are the same (R is a constant and the K given is for a particular temperature) it just depends on delta(n), which is the change in moles between the products and reactants. For the first couple rows on the table, this is just 0 since there are equal moles of products and reactants. And anything raised to the 0 power is just 1, and anything multiplied by 1 doesn't change and thus Kc = Kp. But further down the table, like F2(g) <=> 2F(g) the difference in moles is 1 (2 moles F minus 1 mol F2 = 1)... so that makes Kp and Kc different by a factor of RT.

The same logic follows for the other different values :) just count the difference in moles to know if Kc and Kp are same or different.

Shreya Ramineni 2L
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Re: Table 11.2

Postby Shreya Ramineni 2L » Mon Dec 04, 2017 3:19 pm

K=Kp which is for gases and partial pressures but Kc is for molarity.

Jessica Nunez 1I
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Joined: Thu Jul 13, 2017 3:00 am

Re: Table 11.2

Postby Jessica Nunez 1I » Mon Dec 04, 2017 3:22 pm

To add on, K = Kp is for gases and it is denoted by the units atm (bar, torr, Pa etc.). Kc is for concentration which is denoted by molarity units.

Suhail Zaveri
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Re: Table 11.2

Postby Suhail Zaveri » Mon Dec 04, 2017 4:54 pm


There are many K’s even ones for dissolving called Ksp which is for dissolving. Also It is different than Kc also Kp is different as there is a calculation to convert Kc to Kp so they can be different.

Hope this helps

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