11.41

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mhuang 1E
Posts: 22
Joined: Fri Sep 29, 2017 7:05 am

11.41

Postby mhuang 1E » Fri Dec 01, 2017 12:33 am

I had a question regarding finding the number of moles for the mols of NH3 formed in the rxn: NH4(NH2CO2)(S) ⇋ 2NH3(g) + O2(g). The solutions manual uses the moles fo CO2 to find the number of mols for NH3 (2 mol of NH3 formed per mol of CO2; number of mol for NH3= 2x3.95x10^-4 = 7.90 x10^-4). But, I was wondering why you can't use # of mol for NH4(NH2CO2) to find the number of mols for NH3 (which by the same concept, would yield a different answer: # mol NH3= 2 x mol NH4(NH2CO2)= 2 x 0.320 = 0.640 mol NH3).

Jasmin Tran 1J
Posts: 54
Joined: Thu Jul 27, 2017 3:00 am

Re: 11.41

Postby Jasmin Tran 1J » Fri Dec 01, 2017 12:46 am

The reason why you cannot use the number of mols for NH4(NH2CO2) to find the number of mols for NH3 is because, in this case, NH4(NH2CO2) is a reactant and NH3 and CO2 are the products. For this problem (and others), you would have to use one product to find another in order to yield the correct answer. Since you find the mols of CO2 produced, you can then use the balanced equation to find the mols of NH3 produced which is multiplying mols of CO2 by 2 since that is the ratio shown in the equation.

Hope this helps!


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