Reverse Reactions  [ENDORSED]

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welcometochillis
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Reverse Reactions

Postby welcometochillis » Sun Dec 03, 2017 10:32 pm

If the k value for a system in equilibrium is a number, will it's reverse reaction be the same number? I assume yes because the rate at which products and reactants "go" into another should be the same?

Carlos Gonzales 1H
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Re: Reverse Reactions

Postby Carlos Gonzales 1H » Sun Dec 03, 2017 10:36 pm

The K value of the reverse reaction will be the reciprocal of the forward reaction, so the reverse reaction will be 1/K.

Kathleen Vidanes 1E
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Joined: Fri Sep 29, 2017 7:07 am

Re: Reverse Reactions

Postby Kathleen Vidanes 1E » Sun Dec 03, 2017 10:37 pm

No,the K value for the reverse reaction would be the inverse of the forward reaction. Using the example given in class, if the K value for the forward reaction = 61.0, the K value for the reverse reaction will = 1/61.0 or 0.016

CameronJohari1J
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Re: Reverse Reactions  [ENDORSED]

Postby CameronJohari1J » Sun Dec 03, 2017 10:37 pm

The k value of the reverse reaction is inverse of k.
If k is the equilibrium value for A+B<-->C K=C/(A*B)
then C<-->A+B 1/K=(A*B)/C


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