Page 1 of 1
Reverse Reactions
Posted: Sun Dec 03, 2017 10:32 pm
by welcometochillis
If the k value for a system in equilibrium is a number, will it's reverse reaction be the same number? I assume yes because the rate at which products and reactants "go" into another should be the same?
Re: Reverse Reactions
Posted: Sun Dec 03, 2017 10:36 pm
by Carlos Gonzales 1H
The K value of the reverse reaction will be the reciprocal of the forward reaction, so the reverse reaction will be 1/K.
Re: Reverse Reactions
Posted: Sun Dec 03, 2017 10:37 pm
by Kathleen Vidanes 1E
No,the K value for the reverse reaction would be the inverse of the forward reaction. Using the example given in class, if the K value for the forward reaction = 61.0, the K value for the reverse reaction will = 1/61.0 or 0.016
Re: Reverse Reactions [ENDORSED]
Posted: Sun Dec 03, 2017 10:37 pm
by CameronJohari1J
The k value of the reverse reaction is inverse of k.
If k is the equilibrium value for A+B<-->C K=C/(A*B)
then C<-->A+B 1/K=(A*B)/C