Lyndon's Week 9 WS #7 Clarification Question

Moderators: Chem_Mod, Chem_Admin

Hena Sihota 1L
Posts: 51
Joined: Fri Sep 29, 2017 7:07 am
Been upvoted: 2 times

Lyndon's Week 9 WS #7 Clarification Question

Postby Hena Sihota 1L » Sat Dec 09, 2017 3:47 pm

Number 7 asks: From number 1, SO3(g)<-->SO2(g)+O2(g). The Kc of the reverse reaction is 5.66*10^(-10). What are the equilibrium concentrations of all the products and reactants if you first introduce a 0.522M sample of SO2 with a 0.633M sample of O2?
I have 2 questions regarding questions similar to this one:
1) Suppose everything in the question was the same except the Kc of the forward reaction was given. You would have to take the inverse of that Kc to get the Kc of the reverse reaction and then solve for x, right?
2) Suppose everything in the question was the same except you were given the concentration of SO3 instead of the concentrations of SO2 and O2. You would have to take the inverse of the Kc given to get the Kc of the forward reaction because in this new scenario the forward reaction would be favored, right?

Chem_Mod
Posts: 16975
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 364 times

Re: Lyndon's Week 9 WS #7 Clarification Question

Postby Chem_Mod » Sat Dec 09, 2017 4:25 pm

Yes for all your questions. K is usually given for a specific direction. In problems, you will have to determine which direction the reaction is actually going in and make sure the K you are using is correct. Sometimes if you have concentrations of both reactants and products, you will have to solve for Q and compare it to K to figure out which direction the reaction will go.

-L


Return to “Equilibrium Constants & Calculating Concentrations”

Who is online

Users browsing this forum: No registered users and 4 guests