11.89

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Kathleen Vidanes 1E
Posts: 62
Joined: Fri Sep 29, 2017 7:07 am

11.89

Postby Kathleen Vidanes 1E » Sat Dec 09, 2017 6:40 pm

For 11.89b, why are the partial pressures divided by 100?

Silvino Jimenez 1A
Posts: 52
Joined: Fri Sep 29, 2017 7:04 am

Re: 11.89

Postby Silvino Jimenez 1A » Sun Dec 10, 2017 10:16 am

If you notice the units on the y-axis of graph are in

kPa


We calculate equilibrium constants in


atm (atmospheres)



I am assuming a unit conversion was made when dividing by 100 since


1 atm = 101.3 kPa ~ 100 kPa



:)


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