11.89
Posted: Sat Dec 09, 2017 6:40 pm
For 11.89b, why are the partial pressures divided by 100?
If you notice the units on the y-axis of graph are in
kPa
We calculate equilibrium constants in
atm (atmospheres)
I am assuming a unit conversion was made when dividing by 100 since
1 atm = 101.3 kPa ~ 100 kPa
:)