Help with question 11.43 6th edition  [ENDORSED]

Moderators: Chem_Mod, Chem_Admin

Ashley Kenney 1E
Posts: 32
Joined: Wed Nov 14, 2018 12:23 am

Help with question 11.43 6th edition

Postby Ashley Kenney 1E » Wed Jan 09, 2019 10:55 pm

When determining the equilibrium relation, I understand where the terms x^2 and 2x come from, but I don't quite understand why we subtract 2x from the initial partial pressure of NO to create the expression of 1-2x. Can someone please explain this? Thank you!

Tam To 1B
Posts: 72
Joined: Fri Sep 28, 2018 12:25 am

Re: Help with question 11.43 6th edition  [ENDORSED]

Postby Tam To 1B » Thu Jan 10, 2019 11:09 am

On the ICE table, you have to find initial molar concentration, change in molar concentration, and the equilibrium molar concentration. Since you are initially given 1.0 mol/L NO, the change would be -2x since you have the coefficient 2NO in the reaction. In order to calculate equilibrium, you subtract the change from the initial which then gives you 1.0-2x as the equilibrium molar concentration of NO.

Ashley Kenney 1E
Posts: 32
Joined: Wed Nov 14, 2018 12:23 am

Re: Help with question 11.43 6th edition

Postby Ashley Kenney 1E » Thu Jan 10, 2019 9:11 pm

Oh that makes sense. Thank you!


Return to “Equilibrium Constants & Calculating Concentrations”

Who is online

Users browsing this forum: No registered users and 2 guests