Page 1 of 1
Help with question 11.43 6th edition
Posted: Wed Jan 09, 2019 10:55 pm
When determining the equilibrium relation, I understand where the terms x^2 and 2x come from, but I don't quite understand why we subtract 2x from the initial partial pressure of NO to create the expression of 1-2x. Can someone please explain this? Thank you!
Re: Help with question 11.43 6th edition [ENDORSED]
Posted: Thu Jan 10, 2019 11:09 am
On the ICE table, you have to find initial molar concentration, change in molar concentration, and the equilibrium molar concentration. Since you are initially given 1.0 mol/L NO, the change would be -2x since you have the coefficient 2NO in the reaction. In order to calculate equilibrium, you subtract the change from the initial which then gives you 1.0-2x as the equilibrium molar concentration of NO.
Re: Help with question 11.43 6th edition
Posted: Thu Jan 10, 2019 9:11 pm
Oh that makes sense. Thank you!