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Help with question 11.43 6th edition

Posted: Wed Jan 09, 2019 10:55 pm
by Ashley Kenney 1E
When determining the equilibrium relation, I understand where the terms x^2 and 2x come from, but I don't quite understand why we subtract 2x from the initial partial pressure of NO to create the expression of 1-2x. Can someone please explain this? Thank you!

Re: Help with question 11.43 6th edition  [ENDORSED]

Posted: Thu Jan 10, 2019 11:09 am
by Tam To 1B
On the ICE table, you have to find initial molar concentration, change in molar concentration, and the equilibrium molar concentration. Since you are initially given 1.0 mol/L NO, the change would be -2x since you have the coefficient 2NO in the reaction. In order to calculate equilibrium, you subtract the change from the initial which then gives you 1.0-2x as the equilibrium molar concentration of NO.

Re: Help with question 11.43 6th edition

Posted: Thu Jan 10, 2019 9:11 pm
by Ashley Kenney 1E
Oh that makes sense. Thank you!