6th edition 11.23

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Anushi Patel 1J
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Joined: Fri Sep 28, 2018 12:19 am
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6th edition 11.23

Postby Anushi Patel 1J » Thu Jan 10, 2019 7:07 pm

Can someone share how they solved 11.23? I think I have the concept down but I can't seem to get the right answer.

Xinyi Zeng 4C
Posts: 63
Joined: Fri Sep 28, 2018 12:18 am

Re: 6th edition 11.23

Postby Xinyi Zeng 4C » Thu Jan 10, 2019 7:48 pm

Try to write out the expression for Kc=[BrCl]^2/([Br2][Cl2]), and then sub in the values for Kc and concentrations of BrCl and Cl2. I got my answer this way.

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