ICE Table Help

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Dayna Pham 1I
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Joined: Fri Sep 28, 2018 12:16 am
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ICE Table Help

Postby Dayna Pham 1I » Fri Jan 11, 2019 12:25 pm

Hello! In the example given on Wednesday, we did the ICE table on ATP hydrolysis.
It was given that the initial molarity of ATP in healthy muscle tissue is 8.435 x 10^-3. We determined that the change in molarity was - 8.435 x 10^-3. I thought that if we subtracted the change from the initial, we would end up with zero.

Could someone explain mathematically how subtracting the change from the initial results in the given equilibrium molarity, 7.214 x 10^-11?

Thanks!

Emmaraf 1K
Posts: 94
Joined: Sat Oct 20, 2018 12:16 am

Re: ICE Table Help

Postby Emmaraf 1K » Fri Jan 11, 2019 1:00 pm

I think you might be looking back at the problem in the wrong order from when we took the notes. It was given that the dead muscle tissue has an ATP concentration at equilibrium 7.214x10^-11 but that originally it was 8.435x10^-3. We didn't solve for the 7.214x10^-11 value since it was give to us. We did solve for the change in concentration of the ATP in order to solve for x by subtracting initial from final to get the .008 as you mentioned. The question was only asking for the dead muscle equilibrium concentration of the ADP and P since it was already provided for the ATP. Therefore, the solution is just x for both ADP and P concentration in dead muscle tissue (since concentration of ATP and P started out as 0 and increased each by x due to stoichiometric coefficients) which as I said was .008.

Faith Fredlund 1H
Posts: 68
Joined: Fri Sep 28, 2018 12:18 am

Re: ICE Table Help

Postby Faith Fredlund 1H » Fri Jan 11, 2019 3:00 pm

In addition to this question, I was wondering how I would know when to use an ICE table. Are there any key words or given information that would help indicate when I should use this tool? Thanks!

michelle
Posts: 62
Joined: Fri Sep 28, 2018 12:23 am

Re: ICE Table Help

Postby michelle » Fri Jan 11, 2019 4:48 pm

The is no keyword I think. But it always works in equilibrium problems.


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