6th edition 11.71

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Jeremiah Hutauruk
Posts: 67
Joined: Fri Sep 28, 2018 12:28 am

6th edition 11.71

Postby Jeremiah Hutauruk » Fri Jan 11, 2019 3:40 pm

11.71 The four gases NH3, O2, NO, and H2O are mixed
in a reaction vessel and allowed to reach equilibrium in the reaction 4 NH3(g) 5 O2(g) ∆ 4 NO(g) 6 H2O(g). Certain changes (see the following table) are then made to this mixture. Considering each change separately, state the effect (increase, decrease, or no change) that the change has on the original equilibrium values of the quantity in the second column (or K, if that is specified). The temperature and volume are constant.
the effect (increase, decrease, or no change) that the change has on the original equilibrium value of the quantity in the second column (or K, if that is specified). The temperature and volume are constant.
Change
(a) add NO
(b) add NO
(c) remove H2O (d) remove O2 (e) add NH3
(f) remove NO (g) add NH3
Quantity
amount of H2O amount of O2 amount of NO amount of NH3 K
amount of NH3 amount of O2

Xuan Kuang 2L
Posts: 31
Joined: Wed Nov 14, 2018 12:23 am

Re: 6th edition 11.71

Postby Xuan Kuang 2L » Fri Jan 11, 2019 7:28 pm

Not sure if you wanted all of the answers, but I provided them all down below with some explanations. Hope it helps!
a) When you add NO, Q>K, so more reactants are formed. This means more products are used up, so the amount of H2O, which we assume is constant and hasn't changed in concentration, decreases.
b) The same reasoning as part a), but since we're discussing the amount of O2, which is on the reactants' side, the concentration of O2 increases.
c) When you remove H2O, the reactants will minimize this effect by creating more products, so the concentration of NO increases
d) When you remove O2, reaction will minimize this by forming more reactants, so the amount of NH3 subsequently increases
e) Because we just learned that adding/removing concentration has no effect of K, which is temperature-dependent, we say that it has no effect on K
f) Removal of NO will be minimized by forming more products, decreasing the amount of NH3
g) Adding NH3 will favor the forward reaction, decreasing the amount of O2.


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