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Solids and Liquids in Rxn

Posted: Fri Jan 11, 2019 4:07 pm
by Madison Hurst
What would K be if the reaction was only made up of solids and liquids, no gases or aq solutions?

Re: Solids and Liquids in Rxn

Posted: Fri Jan 11, 2019 4:08 pm
by sophiebillings1E
I believe since solids and liquids are considered 1 in the equation K=1

Re: Solids and Liquids in Rxn

Posted: Fri Jan 11, 2019 7:04 pm
by Erin Kim 2G
Solids and liquids are not included in the equilibrium constant equation. They are put in as a value of 1 and only gases and aqueous elements are considered when solving for the equilibrium constant.

Re: Solids and Liquids in Rxn

Posted: Sat Jan 12, 2019 10:45 am
by Rami_Z_AbuQubo_2K
If it was solids and liquids, then there would not be an equilibrium constant. There is no such thing as a concentration of a solid. Additionally, for pure liquids, they do not react significantly in the reaction. This means that the amount of pure liquid in the reactants is almost the same as that in the products and so they eventually cancel out in the ration of products to reacts. Essentially, it is just unnecessary to use them in the calculation.

Re: Solids and Liquids in Rxn

Posted: Sat Jan 12, 2019 12:19 pm
by MichaelMoreno2G
In response to the responses above me, why would solids and liquids not apply to the equilibrium constant?

Re: Solids and Liquids in Rxn

Posted: Sat Jan 12, 2019 12:27 pm
by Chem_Mod
There are very very few reactions (if any at all) in which a pure solid and liquid react to yield another pure solid or liquid. If a pure solid and liquid did react, the resulting product would be dissolved to some extent in the pure liquid and thus have a concentration which would appear in the equilibrium equation.

Re: Solids and Liquids in Rxn

Posted: Sat Jan 12, 2019 4:53 pm
by Anand Narayan 1G
If the reaction was only made up of solids and liquids, then K would be equal to 1.