Liquids and Solids
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Liquids and Solids
Why aren't reactants and products in the liquid and solid phases not included when calculating K?
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Re: Liquids and Solids
I think Professor Lavelle said it's because solids and liquids aren't changed in concentration during the reaction.
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Re: Liquids and Solids
Solids have a concentration of 1, which doesn't change anything in the equilibrium concentration equation.
For example, C(s)+ O(g) <-> CO(g), if Carbon was included in K because it was, it would be [CO]/[O]*1 which is just [CO]/[O].
You don't want to include the concentration of Carbon though, as it may show a lack of understanding in concentrations.
Hope this helps and correct me if I'm wrong.
For example, C(s)+ O(g) <-> CO(g), if Carbon was included in K because it was, it would be [CO]/[O]*1 which is just [CO]/[O].
You don't want to include the concentration of Carbon though, as it may show a lack of understanding in concentrations.
Hope this helps and correct me if I'm wrong.
Re: Liquids and Solids
Solids and liquids (pure substances) are incompressible and concentration don't change (or change very insignificantly) throughout the reaction. For example, pure water in the liquid or solid phase is 100% water and incompressible. Hence, water doesn't influence the reaction.
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