3 posts • Page 1 of 1
On question 5I.17 in the 7th ed., there is a step in the solutions manual that goes from 2x=(3.16x10^-3)(0.114-x) followed by the step 2.00316x=3.60x10^-4. Can someone explain the work process in between those steps or how to get from that first step to the next?
Multiply the right hand of the equation out. Doing so gives you 2x=3.60x10^-4 - 3.16x10^-3x (multiply 3.16x10^-3 in the first parenthesis with both terms in the second parenthesis). To solve for x add the 3.16x10^-3x from the right hand side of the equation to the 2x on the left. This gives you 2.00316x=3.60x10^-4. To isolate x from here, divide both sides by 2.00316. Hope this helped!
Who is online
Users browsing this forum: No registered users and 2 guests