Solving for x in ICE table

[JulieAljamal1E]

On question 5I.17 in the 7th ed., there is a step in the solutions manual that goes from 2x=(3.16x10^-3)(0.114-x) followed by the step 2.00316x=3.60x10^-4. Can someone explain the work process in between those steps or how to get from that first step to the next?

[Kavvya Gupta 1H]

you multiply (3.16*10^-3) with (0.114-x) getting 2x= (3.6*10^-4)-(3.16*10^-3)x. Then you get the x on one side getting 2.00316=3.6*10^-4

[105114680]

Multiply the right hand of the equation out. Doing so gives you 2x=3.60x10^-4 - 3.16x10^-3x (multiply 3.16x10^-3 in the first parenthesis with both terms in the second parenthesis). To solve for x add the 3.16x10^-3x from the right hand side of the equation to the 2x on the left. This gives you 2.00316x=3.60x10^-4. To isolate x from here, divide both sides by 2.00316. Hope this helped!