When we calculate pOH for Ba(OH)2, why do we multiply the concentration by two?
Is it because there's two OH?
Calculate pOH
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 31
- Joined: Fri Sep 28, 2018 12:20 am
Re: Calculate pOH
To put it simply, yes.
The chemical equation of the dissociation of Ba(OH)2 is Ba(OH)2 -> 2OH- + Ba2+
This indicates that in the dissociation of Ba(OH)2, 2 hydroxide ions form.
The chemical equation of the dissociation of Ba(OH)2 is Ba(OH)2 -> 2OH- + Ba2+
This indicates that in the dissociation of Ba(OH)2, 2 hydroxide ions form.
-
- Posts: 57
- Joined: Fri Sep 28, 2018 12:18 am
-
- Posts: 76
- Joined: Fri Sep 28, 2018 12:24 am
Re: Calculate pOH
You have to multiply the concentration by two because of the molar ratio between Ba(OH)2 and hydroxide ions. If you don't recognize the difference in moles, your calculation and pH will be way off. Another reason why it's so important to have a balanced reaction before your start making any assumptions or calculations.
Return to “Equilibrium Constants & Calculating Concentrations”
Who is online
Users browsing this forum: No registered users and 9 guests