HW Question 11.89

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Netpheel Wang 4L
Posts: 60
Joined: Fri Sep 28, 2018 12:15 am

HW Question 11.89

Postby Netpheel Wang 4L » Tue Jan 15, 2019 6:31 pm

The solution manual gives the equation as 2A(g) -> B(g) + 2C(g)
Where are the coefficients coming from?

The calculation of the Kp is given as ((5/100)(10/100)^2)/(18/100)^2=1.54x10^-2
Why are the values over 100?
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jonathanjchang2E
Posts: 61
Joined: Fri Sep 28, 2018 12:26 am

Re: HW Question 11.89

Postby jonathanjchang2E » Tue Jan 15, 2019 6:35 pm

You find the coefficients by setting up an ice table since they give you the initial and final partial pressures. So the initial for A is 28, B is 0, and C is 0. The final for A is 18, B is 5, and C is 10. From this you know that the change for A is -2X, for B is +X, and C is +2X because it would only make sense for X to be 5. I don't know why they divided the values by 100.


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