Chemical Equilibrium Part 3 Post-Assessment

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JulieAljamal1E
Posts: 71
Joined: Fri Sep 28, 2018 12:24 am

Chemical Equilibrium Part 3 Post-Assessment

Postby JulieAljamal1E » Tue Jan 15, 2019 6:39 pm

Can someone explain how to solve number 20 on the post-assessment 3? I understand how to set up the table but why in the given table for the equilibrium concentration do they say c+2x for 2SO3 and not just 2x. How do you solve for the c? A vial of SO2 (0.522 mol.L-1) and O2 (0.633 mol.L-1) react and reach equilibrium. Calculate the equilibrium concentrations of the products and reactants given that KC = 5.66 x 10-10 for this reaction: 2 SO2 (g) + O2 (g) ⇌ 2 SO3 (g).

Andrea Zheng 1H
Posts: 61
Joined: Fri Sep 28, 2018 12:26 am

Re: Chemical Equilibrium Part 3 Post-Assessment

Postby Andrea Zheng 1H » Wed Jan 16, 2019 12:14 am

I believe it should just be +2x, not c+2x, because I used eq composition of SO3 to be 2x to solve the problem and it said I got the correct answer. The c may have come from problem 12, where you were asked to find what the value of c would be (where c=+2x)


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