using ICE when you have a product concentration

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Tinisha 1G
Posts: 69
Joined: Fri Sep 28, 2018 12:17 am

using ICE when you have a product concentration

Postby Tinisha 1G » Wed Jan 16, 2019 5:30 pm

If the only reactant is a solid, and the problem gives you a concentration for one of the products, can someone explain why for the initial change it is still positive x for both of the products?
Thanks!

Clarissa Cabil 1I
Posts: 66
Joined: Fri Sep 28, 2018 12:19 am

Re: using ICE when you have a product concentration

Postby Clarissa Cabil 1I » Wed Jan 16, 2019 6:39 pm

Are you referring to the change in molarity and not the initial molarity?

And if you are given an initial concentration of one of the products, you have to find Q to dictate which direction the reaction is going.
If Q<K, the reaction is shifted to the right and favoring the products. So the change in concentration, or x, will be negative for the reactants (because the reactants are being used up in the reaction) and positive for the products.
If Q>K, the reaction is shifted to the left and favoring the reactants. So the change in concentration, or x, will be positive for the reactants (because we need more reactants) and negative for the reactants.

I hope this helps!


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