Textbook 7th edition 6E1

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inlovewithchemistry
Posts: 104
Joined: Fri Sep 28, 2018 12:19 am

Textbook 7th edition 6E1

Postby inlovewithchemistry » Wed Jan 16, 2019 11:40 pm

I have a couple questions about this question that are confusing me.
Why do we need to be doing this set up at all if H2So4 is a strong acid? I thought we did the ICE chart for weak acids?
Does this relate to why there is a "second ionization in the solutions manual? What is that?
Lastly, Where does the equation (x^2+0.162x-1.8E-3=0) come from? How do we calculate this from the Ka equation?
Thank you very much!

Nicklas_Wright_1A
Posts: 60
Joined: Fri Sep 28, 2018 12:23 am

Re: Textbook 7th edition 6E1

Postby Nicklas_Wright_1A » Thu Jan 17, 2019 10:25 am

That is a diprotic acid, meaning it can give off 2 protons per formula unit. The first ionization is when the first proton comes off and the second ionization is when the second one comes off. The acid is strong at first, but when it releases the first proton it becomes HSo4 which is a weak acid. The second proton is less likely to detach than the first one.


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