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12.23 6th Edition

Posted: Thu Jan 17, 2019 9:27 am
by Alexa_Henrie_1I
Hello, I am having trouble solving 12.23. Could someone please explain how to go about it? The question asks:


The value of Kw for water at body temp (37 degrees C) is 2.1x10^-14. A) What is the molarity of H3O ions and the pH of neutral water at 37 degrees C? B) What is the molarity of OH in neutral water at 37 degrees C?

Re: 12.23 6th Edition

Posted: Thu Jan 17, 2019 10:03 am
by Chem_Mod
Remember if it is neutral, the concentration of H3O+ and OH- are the same and their product is equal to the Kw

Re: 12.23 6th Edition

Posted: Thu Jan 17, 2019 3:11 pm
by Alexa_Henrie_1I
Okay I understand how the Kw is equal to to x^2 now. Thank you.