5.61 7th Edition

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paytonm1H
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Joined: Fri Sep 28, 2018 12:18 am

5.61 7th Edition

Postby paytonm1H » Fri Jan 18, 2019 9:56 pm

In problem 5.61 the photosynthesis reaction is given: 6CO2(g) + 6H2O(l) --> C6H12O6(aq) + 6O2(g)

Part (b) asks what the effect would be if the system was compressed. Since there are more moles on the product side (disregarding moles of water on reactant side), I would think that compression would shift toward the formation of reactants.

However, the answer key says that because there are equal numbers of moles of gas on both sides of the equation, there will be little or no effect on compressing the system. Is this because you disregard both the water and the aqueous solution in the equilibrium constant? Why isn't the glucose included??

Thanks

Matthew Tran 1H
Posts: 165
Joined: Fri Sep 28, 2018 12:16 am

Re: 5.61 7th Edition

Postby Matthew Tran 1H » Fri Jan 18, 2019 11:18 pm

Glucose is in the aqueous state, which means it is dissolved in water. Water is incompressible, so liquid water and aqueous solutions are not affected by an increase in pressure/compression.


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