5I.13 (b) - 7th edition - sig figs

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Andie Jian 1D
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5I.13 (b) - 7th edition - sig figs

Postby Andie Jian 1D » Sat Jan 19, 2019 3:33 pm

In this question, we are supposed to calculate the equilibrium composition. I got the quadratic equation 0= 4x2+1.2*10-4x-1.2*10-7, which led to x being 1.6*10-4. [F2]=1.0*10-3-x, so I got the answer 8.4*10-4. However, the answer key gives the answer with just two sig figs, making it 8*10-4. Did I miscalculate the number of sigfigs in this problem?

Ana Pedreros
Posts: 62
Joined: Fri Sep 28, 2018 12:19 am

Re: 5I.13 (b) - 7th edition - sig figs

Postby Ana Pedreros » Sat Jan 19, 2019 5:28 pm

8*10^-4 has one sig fig because you only count the sig figs in the number being multiplied. I believe Lavelle has stated that 2 decimal places for the answer is acceptable for these problems.


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