reaction of AlCl3

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105114680
Posts: 60
Joined: Fri Sep 28, 2018 12:23 am

reaction of AlCl3

Postby 105114680 » Sun Jan 20, 2019 12:02 pm

Hi. The problem 6D.15 part (b) asks to calculate the pH of 0.055M AlCl3. I was confused on how to set up a reaction since hydrogen isn't a part of AlCl3. The solutions manual sets up the following reaction: Al(H2O)6^+3(aq) + H2O(l) <---> H3O^+3(aq) + Al(H2O)5^+2(aq). I understand why the AlCl3 had to be hydrated (it needs an H to give off) but can someone please explain why AlCl3 can act as an acid in the first place and also how to come up with Al(H2O)6^+3. Thank you in advance!

eden tefera 2B
Posts: 39
Joined: Fri Sep 28, 2018 12:21 am

Re: reaction of AlCl3

Postby eden tefera 2B » Sun Jan 20, 2019 3:37 pm

AlCl3 can act as an acid because it accepts electrons.


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