HW Problem #12.79 (6th edition)

Moderators: Chem_Mod, Chem_Admin

Sophia Diaz - Dis 1B
Posts: 73
Joined: Fri Apr 06, 2018 11:02 am
Been upvoted: 1 time

HW Problem #12.79 (6th edition)

Postby Sophia Diaz - Dis 1B » Sun Jan 20, 2019 12:59 pm

When I was looking in the solutions manual to check my answer, it turns out I did this problem wrong.

Instead of using the equation:
H2SO4 + H2O --> H3O + HSO4

you were supposed to use the equation:
HSO4 + H2O --> H3O + SO4

How were you supposed to know that H2SO4 dissociates twice? When will I know when there are other compounds that need to be dissociated twice?

Another question is why is the initial concentration of HSO4 AND H3O 0.15? Wouldn't I have to do an ICE problem in order to figure out those concentrations?

Emily Huang 1E
Posts: 30
Joined: Fri Sep 28, 2018 12:20 am

Re: HW Problem #12.79 (6th edition)

Postby Emily Huang 1E » Sun Jan 20, 2019 1:06 pm

H2SO4 is a strong acid so it dissociates completely. That is why both the hydrogen atoms are deprotonated and you get SO4 as a product

Return to “Equilibrium Constants & Calculating Concentrations”

Who is online

Users browsing this forum: No registered users and 3 guests