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HW Problem #12.79 (6th edition)

Posted: Sun Jan 20, 2019 12:59 pm
by Sophia Diaz - Dis 1B
When I was looking in the solutions manual to check my answer, it turns out I did this problem wrong.

Instead of using the equation:
H2SO4 + H2O --> H3O + HSO4

you were supposed to use the equation:
HSO4 + H2O --> H3O + SO4

How were you supposed to know that H2SO4 dissociates twice? When will I know when there are other compounds that need to be dissociated twice?

Another question is why is the initial concentration of HSO4 AND H3O 0.15? Wouldn't I have to do an ICE problem in order to figure out those concentrations?

Re: HW Problem #12.79 (6th edition)

Posted: Sun Jan 20, 2019 1:06 pm
by Emily Huang 1E
H2SO4 is a strong acid so it dissociates completely. That is why both the hydrogen atoms are deprotonated and you get SO4 as a product