5I.15 7th Ed

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Summer de Vera 2C
Posts: 65
Joined: Fri Sep 28, 2018 12:16 am

5I.15 7th Ed

Postby Summer de Vera 2C » Sun Jan 20, 2019 2:20 pm

Hi! So the problem tells you that NH4HS(s) and .400 mol NH3(g) are in a 2.0L vessel @ 24˚C and that the equilibrium for NH4HS(s) --> <-- NH3(g) + H2S(g) is Kc=1.6x10^-4. You're asked to find the eq [products], however when I do the ICE table, I keep getting that x=0. Is this even possible? Am I doing something wrong/not understanding something conceptually?

Henry Krasner 1C
Posts: 64
Joined: Fri Sep 28, 2018 12:15 am

Re: 5I.15 7th Ed

Postby Henry Krasner 1C » Sun Jan 20, 2019 4:00 pm

The number you get from solving for x is 0.0008, which is very close to 0 but not completely. And although this is typically so small it is ignorable, since it is the x value and there is some change, we must take it into consideration for this problem.

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