Question 5H1

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inlovewithchemistry
Posts: 104
Joined: Fri Sep 28, 2018 12:19 am

Question 5H1

Postby inlovewithchemistry » Mon Jan 21, 2019 11:00 am

The concept presented in this question is confusing me. Why is part b considered the square root of the original equation? In part c, how it is the square of the original equation if 3^2 is 9?

Fayez Kanj
Posts: 62
Joined: Fri Sep 28, 2018 12:18 am
Been upvoted: 1 time

Re: Question 5H1

Postby Fayez Kanj » Mon Jan 21, 2019 12:54 pm

Hello!

Notice that in part (b), all the stoichiometric coefficients have been halved. This means that in the expression for K, all the exponents will also be halved (since exponents in the expression of K correspond to the stoichiometric coefficients.) Halving the exponents essentially means taking the square root.

In part (c), we are doubling the stoichiometric coefficients, so the exponents in the K expression will double, which is equivalent to raising K to the power of 2: K^2

Hope this helps :)

inlovewithchemistry
Posts: 104
Joined: Fri Sep 28, 2018 12:19 am

Re: Question 5H1

Postby inlovewithchemistry » Tue Jan 29, 2019 4:08 pm

Thank you for this reply! After looking back and comparing your answer to some high school notes, this would have been a lifesaver.


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